What are the solutions to the equation n^3+12n^2+48n+64=0 ?

The solutions to the equation n^3+12n^2+48n+64=0 are n=-4

Find the zeros of n^3+12n^2+48n+64=0

The zeros of n^3+12n^2+48n+64=0 are n=-4

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n^{3} + 12 n^{2} + 48 n + 64 = 0

n = - 4

Solution steps

n^{3} + 12 n^{2} + 48 n + 64 = 0

Factor

n^{3} + 12 n^{2} + 48 n + 64 : (n + 4)^{3}

(n + 4)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n + 4 = 0

Solve

n + 4 = 0 : n = - 4

The solution is

n = - 4

x^{3} + 2 = 1

- x^{3} + 2 \cdot x^{2} + x - 2 = 0

300 x^{4} + 480 x^{3} + 180 x^{2} = 0

2 x^{2} - 5 x^{3} + 1 = 0

x^{3} + 2 = 9

What are the solutions to the equation n^3+12n^2+48n+64=0 ?
The solutions to the equation n^3+12n^2+48n+64=0 are n=-4
Find the zeros of n^3+12n^2+48n+64=0
The zeros of n^3+12n^2+48n+64=0 are n=-4