What are the solutions to the equation x^3-40x^2+404x-80=0 ?

The solutions to the equation x^3-40x^2+404x-80=0 are x=20,x=2(5+2sqrt(6)),x=2(5-2sqrt(6))

Find the zeros of x^3-40x^2+404x-80=0

The zeros of x^3-40x^2+404x-80=0 are x=20,x=2(5+2sqrt(6)),x=2(5-2sqrt(6))

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x^{3} - 40 x^{2} + 404 x - 80 = 0

x = 20, x = 2 (5 + 26), x = 2 (5 - 26)

Decimal Notation

x = 20, x = 19.79795 \dots, x = 0.20204 \dots

Solution steps

x^{3} - 40 x^{2} + 404 x - 80 = 0

Factor

x^{3} - 40 x^{2} + 404 x - 80 : (x - 20) (x^{2} - 20 x + 4)

(x - 20) (x^{2} - 20 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 20 = 0 or x^{2} - 20 x + 4 = 0

Solve

x - 20 = 0 : x = 20

Solve

x^{2} - 20 x + 4 = 0 : x = 2 (5 + 26), x = 2 (5 - 26)

The solutions are

x = 20, x = 2 (5 + 26), x = 2 (5 - 26)

(x + 2) (x + 3) (x + 8) (x + 12) = 54 x^{2}

8 x^{3} + 64 x^{2} + 120 x = 0

c^{3} - 8 = 0

x^{3} - x^{2} - 4 x + 8 = 0

v^{4} - 0.8949 v^{2} + 0.028367 = 0

What are the solutions to the equation x^3-40x^2+404x-80=0 ?
The solutions to the equation x^3-40x^2+404x-80=0 are x=20,x=2(5+2sqrt(6)),x=2(5-2sqrt(6))
Find the zeros of x^3-40x^2+404x-80=0
The zeros of x^3-40x^2+404x-80=0 are x=20,x=2(5+2sqrt(6)),x=2(5-2sqrt(6))