What are the solutions to the equation (2x-1)(4x-3)=0 ?

The solutions to the equation (2x-1)(4x-3)=0 are x= 1/2 ,x= 3/4

Find the zeros of (2x-1)(4x-3)=0

The zeros of (2x-1)(4x-3)=0 are x= 1/2 ,x= 3/4

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(2 x - 1) (4 x - 3) = 0

x = \frac{1}{2}, x = \frac{3}{4}

Solution steps

(2 x - 1) (4 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 4 x - 3 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

4 x - 3 = 0 : x = \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{3}{4}

\frac{x}{y}

5 (2 + v) - v = 10 + 4 (v + 1)

6 x^{3} + 13 x^{2} - 4

0 = x^{2} + 6 x - 16

16 x - x^{2} - 48

What are the solutions to the equation (2x-1)(4x-3)=0 ?
The solutions to the equation (2x-1)(4x-3)=0 are x= 1/2 ,x= 3/4
Find the zeros of (2x-1)(4x-3)=0
The zeros of (2x-1)(4x-3)=0 are x= 1/2 ,x= 3/4