What are the solutions to the equation x^3-x^2+1=-6 ?

The solutions to the equation x^3-x^2+1=-6 are x\approx-1.63109…

Find the zeros of x^3-x^2+1=-6

The zeros of x^3-x^2+1=-6 are x\approx-1.63109…

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x^{3} - x^{2} + 1 = - 6

x \approx - 1.63109 \dots

Solution steps

x^{3} - x^{2} + 1 = - 6

Move

6

to the left side

x^{3} - x^{2} + 7 = 0

Find one solution for

x^{3} - x^{2} + 7 = 0

using Newton-Raphson:

x \approx - 1.63109 \dots

Apply long division:

\frac{x ^{3} - x ^{2} + 7}{x + 1.63109 \dots} = x^{2} - 2.63109 \dots x + 4.29158 \dots

x^{2} - 2.63109 \dots x + 4.29158 \dots \approx 0

Find one solution for

x^{2} - 2.63109 \dots x + 4.29158 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 1.63109 \dots

2 x^{4} - 16 x = 0

36 - 12 x - 4 x^{3} = 0

(x - 3)^{3} + 18 = 530

x + 4 = ((x^{2} - 4 x) - 2)^{2}

x^{3} - x^{2} - 8 x + 10 = 0

What are the solutions to the equation x^3-x^2+1=-6 ?
The solutions to the equation x^3-x^2+1=-6 are x\approx-1.63109…
Find the zeros of x^3-x^2+1=-6
The zeros of x^3-x^2+1=-6 are x\approx-1.63109…