What are the solutions to the equation 2x^3+x+1=0 ?

The solutions to the equation 2x^3+x+1=0 are x\approx-0.58975…

Find the zeros of 2x^3+x+1=0

The zeros of 2x^3+x+1=0 are x\approx-0.58975…

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2 x^{3} + x + 1 = 0

x \approx - 0.58975 \dots

Solution steps

2 x^{3} + x + 1 = 0

Find one solution for

2 x^{3} + x + 1 = 0

using Newton-Raphson:

x \approx - 0.58975 \dots

Apply long division:

\frac{2 x ^{3} + x + 1}{x + 0.58975 \dots} = 2 x^{2} - 1.17950 \dots x + 1.69562 \dots

2 x^{2} - 1.17950 \dots x + 1.69562 \dots \approx 0

Find one solution for

2 x^{2} - 1.17950 \dots x + 1.69562 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 0.58975 \dots

x^{4} - 2 x^{3} + 5 x^{2} - 6 = 0

a, 2 f = 5 a^{5}

(x + 1) (x + 2) (x + 3) (x + 6) = - x^{2}

2 = (1 + x)^{4}

y, A = \frac{k y ^{4}}{S}

What are the solutions to the equation 2x^3+x+1=0 ?
The solutions to the equation 2x^3+x+1=0 are x\approx-0.58975…
Find the zeros of 2x^3+x+1=0
The zeros of 2x^3+x+1=0 are x\approx-0.58975…