What are the solutions to the equation 4x^3-12x^2+16=0 ?

The solutions to the equation 4x^3-12x^2+16=0 are x=-1,x=2

Find the zeros of 4x^3-12x^2+16=0

The zeros of 4x^3-12x^2+16=0 are x=-1,x=2

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4 x^{3} - 12 x^{2} + 16 = 0

x = - 1, x = 2

Solution steps

4 x^{3} - 12 x^{2} + 16 = 0

Factor

4 x^{3} - 12 x^{2} + 16 : 4 (x + 1) (x - 2)^{2}

4 (x + 1) (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 1, x = 2

x^{2} (4 x - 3) (5 x - 1) = 0

x^{8} = 1 0^{72}

x^{3} - 7 x^{2} + 13 x - 3 = 0

- x^{3} + 14 x^{2} - 42 x = 0

0 = x^{3} + x^{2} - x - 1

What are the solutions to the equation 4x^3-12x^2+16=0 ?
The solutions to the equation 4x^3-12x^2+16=0 are x=-1,x=2
Find the zeros of 4x^3-12x^2+16=0
The zeros of 4x^3-12x^2+16=0 are x=-1,x=2