What are the solutions to the equation (3p+7)(3p-7)(p+8)=0 ?

The solutions to the equation (3p+7)(3p-7)(p+8)=0 are p=-7/3 ,p= 7/3 ,p=-8

Find the zeros of (3p+7)(3p-7)(p+8)=0

The zeros of (3p+7)(3p-7)(p+8)=0 are p=-7/3 ,p= 7/3 ,p=-8

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(3 p + 7) (3 p - 7) (p + 8) = 0

p = - \frac{7}{3}, p = \frac{7}{3}, p = - 8

Decimal Notation

p = - 2.33333 \dots, p = 2.33333 \dots, p = - 8

Solution steps

(3 p + 7) (3 p - 7) (p + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 p + 7 = 0 or 3 p - 7 = 0 or p + 8 = 0

Solve

3 p + 7 = 0 : p = - \frac{7}{3}

Solve

3 p - 7 = 0 : p = \frac{7}{3}

Solve

p + 8 = 0 : p = - 8

The solutions are

p = - \frac{7}{3}, p = \frac{7}{3}, p = - 8

x \cdot (2 x - 4)^{2} = 0

x, 3 x^{3} + x^{2} - 8 x + 4 = 0

\frac{5 x - 6}{3} = x^{5}

f = f^{5}

d^{3} = 729

What are the solutions to the equation (3p+7)(3p-7)(p+8)=0 ?
The solutions to the equation (3p+7)(3p-7)(p+8)=0 are p=-7/3 ,p= 7/3 ,p=-8
Find the zeros of (3p+7)(3p-7)(p+8)=0
The zeros of (3p+7)(3p-7)(p+8)=0 are p=-7/3 ,p= 7/3 ,p=-8