What are the solutions to the equation 48.46x^3+12.6x-0.005=0 ?

The solutions to the equation 48.46x^3+12.6x-0.005=0 are x\approx 0.00039…

Find the zeros of 48.46x^3+12.6x-0.005=0

The zeros of 48.46x^3+12.6x-0.005=0 are x\approx 0.00039…

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48.46 x^{3} + 12.6 x - 0.005 = 0

x \approx 0.00039 \dots

Solution steps

48.46 x^{3} + 12.6 x - 0.005 = 0

Multiply both sides by

1000

48460 x^{3} + 12600 x - 5 = 0

Find one solution for

48460 x^{3} + 12600 x - 5 = 0

using Newton-Raphson:

x \approx 0.00039 \dots

Apply long division:

\frac{48460 x ^{3} + 12600 x - 5}{x - 0.00039 \dots} = 48460 x^{2} + 19.23014 \dots x + 12600.00763 \dots

48460 x^{2} + 19.23014 \dots x + 12600.00763 \dots \approx 0

Find one solution for

48460 x^{2} + 19.23014 \dots x + 12600.00763 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 0.00039 \dots

10 x^{4} + 3 x^{2} = 1

3 x^{5} = 5 x^{3}

x^{4} + x^{2} + 4 = 0

- 13 + 8 x^{3} = - 77

36 y^{2} - 27 y = 12 y^{3}

What are the solutions to the equation 48.46x^3+12.6x-0.005=0 ?
The solutions to the equation 48.46x^3+12.6x-0.005=0 are x\approx 0.00039…
Find the zeros of 48.46x^3+12.6x-0.005=0
The zeros of 48.46x^3+12.6x-0.005=0 are x\approx 0.00039…