What are the solutions to the equation (3v-21)(v^2+7v+10)=0 ?

The solutions to the equation (3v-21)(v^2+7v+10)=0 are v=7,v=-2,v=-5

Find the zeros of (3v-21)(v^2+7v+10)=0

The zeros of (3v-21)(v^2+7v+10)=0 are v=7,v=-2,v=-5

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(3 v - 21) (v^{2} + 7 v + 10) = 0

v = 7, v = - 2, v = - 5

Solution steps

(3 v - 21) (v^{2} + 7 v + 10) = 0

Factor

(3 v - 21) (v^{2} + 7 v + 10) : 3 (v - 7) (v + 2) (v + 5)

3 (v - 7) (v + 2) (v + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v - 7 = 0 or v + 2 = 0 or v + 5 = 0

Solve

v - 7 = 0 : v = 7

Solve

v + 2 = 0 : v = - 2

Solve

v + 5 = 0 : v = - 5

The solutions are

v = 7, v = - 2, v = - 5

25 x = 50 x^{3}

x^{3} + 1728 = 0

x^{4} - 5 x^{3} + 8 x^{2} - x - 5 = 0

d^{3} = 125

(x) = x^{3} + 2 x^{2} - 5 x - 6

What are the solutions to the equation (3v-21)(v^2+7v+10)=0 ?
The solutions to the equation (3v-21)(v^2+7v+10)=0 are v=7,v=-2,v=-5
Find the zeros of (3v-21)(v^2+7v+10)=0
The zeros of (3v-21)(v^2+7v+10)=0 are v=7,v=-2,v=-5