What are the solutions to the equation d^3=125 ?

The solutions to the equation d^3=125 are d=5,d=-5/2+(5sqrt(3))/2 i,d=-5/2-(5sqrt(3))/2 i

Find the zeros of d^3=125

The zeros of d^3=125 are d=5,d=-5/2+(5sqrt(3))/2 i,d=-5/2-(5sqrt(3))/2 i

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d^{3} = 125

d = 5, d = - \frac{5}{2} + \frac{5 3}{2} i, d = - \frac{5}{2} - \frac{5 3}{2} i

Solution steps

d^{3} = 125

For

x^{3} = f (a)

the solutions are

Simplify

d = 5, d = - \frac{5}{2} + \frac{5 3}{2} i, d = - \frac{5}{2} - \frac{5 3}{2} i

(x) = x^{3} + 2 x^{2} - 5 x - 6

R, 1 R = R^{1} + R^{2} R^{1} X R^{2}

t^{4} = 1

z, z^{5} = - 32

x^{3} - 2 x^{2} - x + 1 = x^{2} - 3 x + 1

What are the solutions to the equation d^3=125 ?
The solutions to the equation d^3=125 are d=5,d=-5/2+(5sqrt(3))/2 i,d=-5/2-(5sqrt(3))/2 i
Find the zeros of d^3=125
The zeros of d^3=125 are d=5,d=-5/2+(5sqrt(3))/2 i,d=-5/2-(5sqrt(3))/2 i