What are the solutions to the equation z^4=-1+sqrt(3)i ?

The solutions to the equation z^4=-1+sqrt(3)i are

Find the zeros of z^4=-1+sqrt(3)i

The zeros of z^4=-1+sqrt(3)i are

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z^{4} = - 1 + 3 i

Solution steps

z^{4} = - 1 + 3 i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 4, a = - 1 + 3 i

∣ a ∣ = 2

ar g (a) = - \frac{π}{3} + π

Simplify

x = - 1.3 x^{3} - 4 x^{2} - 13 x - 6

(\frac{1}{5}) x^{5} = 1

8 x^{12} = 6 x + 4

2 x - 712 - 4 - x^{6} = 1920

(7 x + 1) (5 x^{3} - 10 x^{2}) = 0

What are the solutions to the equation z^4=-1+sqrt(3)i ?
The solutions to the equation z^4=-1+sqrt(3)i are
Find the zeros of z^4=-1+sqrt(3)i
The zeros of z^4=-1+sqrt(3)i are