What are the solutions to the equation x^4-3x^3+5x^2-27x-36=0 ?

The solutions to the equation x^4-3x^3+5x^2-27x-36=0 are x=-1,x=4,x=3i,x=-3i

Find the zeros of x^4-3x^3+5x^2-27x-36=0

The zeros of x^4-3x^3+5x^2-27x-36=0 are x=-1,x=4,x=3i,x=-3i

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x^{4} - 3 x^{3} + 5 x^{2} - 27 x - 36 = 0

x = - 1, x = 4, x = 3 i, x = - 3 i

Solution steps

x^{4} - 3 x^{3} + 5 x^{2} - 27 x - 36 = 0

Factor

x^{4} - 3 x^{3} + 5 x^{2} - 27 x - 36 : (x + 1) (x - 4) (x^{2} + 9)

(x + 1) (x - 4) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 4 = 0 or x^{2} + 9 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 4 = 0 : x = 4

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - 1, x = 4, x = 3 i, x = - 3 i

x^{5} - x^{4} - x^{3} + x^{2} = 0

(1 + \frac{x}{12})^{12} = 0.12

m^{3} - 2 m^{2} + m = 0

4 x^{3} - 6 = 0

- 8 x^{3} + 18 x = 0

What are the solutions to the equation x^4-3x^3+5x^2-27x-36=0 ?
The solutions to the equation x^4-3x^3+5x^2-27x-36=0 are x=-1,x=4,x=3i,x=-3i
Find the zeros of x^4-3x^3+5x^2-27x-36=0
The zeros of x^4-3x^3+5x^2-27x-36=0 are x=-1,x=4,x=3i,x=-3i