What are the solutions to the equation 2^n=3.6*1φ^{13} ?

The solutions to the equation 2^n=3.6*1φ^{13} are φ=\sqrt[13]{(5*2^{n-1})/9}

Find the zeros of 2^n=3.6*1φ^{13}

The zeros of 2^n=3.6*1φ^{13} are φ=\sqrt[13]{(5*2^{n-1})/9}

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2^{n} = 3.6 \cdot 1 φ^{13}

Solution steps

2^{n} = 3.6 \cdot 1 \cdot φ^{13}

Switch sides

3.6 \cdot 1 \cdot φ^{13} = 2^{n}

Multiply both sides by

10

36 φ^{13} = 5 \cdot 2^{n + 1}

Divide both sides by

36

φ^{13} = \frac{5 \cdot 2 ^{n - 1}}{9}

For

x^{n} = f (a)

, n is odd, the solution is

10 c^{5} c + 16.5 = 13.5 + 10 c

x^{3} - 6 x^{2} + 2 x + 24 = 0

x^{3} - 4 x^{2} + x = 0

x^{4} - 5 x^{6} = x + 1

1000000 = 100000 (x^{20})

What are the solutions to the equation 2^n=3.6*1φ^{13} ?
The solutions to the equation 2^n=3.6*1φ^{13} are φ=\sqrt[13]{(5*2^{n-1})/9}
Find the zeros of 2^n=3.6*1φ^{13}
The zeros of 2^n=3.6*1φ^{13} are φ=\sqrt[13]{(5*2^{n-1})/9}