What are the solutions to the equation 2x^3-4x^2-10x+12=0 ?

The solutions to the equation 2x^3-4x^2-10x+12=0 are x=1,x=-2,x=3

Find the zeros of 2x^3-4x^2-10x+12=0

The zeros of 2x^3-4x^2-10x+12=0 are x=1,x=-2,x=3

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2 x^{3} - 4 x^{2} - 10 x + 12 = 0

x = 1, x = - 2, x = 3

Solution steps

2 x^{3} - 4 x^{2} - 10 x + 12 = 0

Factor

2 x^{3} - 4 x^{2} - 10 x + 12 : 2 (x - 1) (x + 2) (x - 3)

2 (x - 1) (x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = - 2, x = 3

q^{(4)} - q^{(2)} - 6 = 0

x^{8} - 4 x^{6} + 4 x^{4} - 1 = 0

11 r + 15 = r^{2} r^{2}

x^{3} + 2 x^{2} - x - 1 = 0

(x^{2} + 2 x + 20)^{2} = 0

What are the solutions to the equation 2x^3-4x^2-10x+12=0 ?
The solutions to the equation 2x^3-4x^2-10x+12=0 are x=1,x=-2,x=3
Find the zeros of 2x^3-4x^2-10x+12=0
The zeros of 2x^3-4x^2-10x+12=0 are x=1,x=-2,x=3