What are the solutions to the equation (x^2+2x+20)^2=0 ?

The solutions to the equation (x^2+2x+20)^2=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i

Find the zeros of (x^2+2x+20)^2=0

The zeros of (x^2+2x+20)^2=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i

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(x^{2} + 2 x + 20)^{2} = 0

x = - 1 + 19 i, x = - 1 - 19 i

Solution steps

(x^{2} + 2 x + 20)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} + 2 x + 20 = 0 : x = - 1 + 19 i, x = - 1 - 19 i

The solutions are

x = - 1 + 19 i, x = - 1 - 19 i

h^{3} = 1

x^{3} + 3 x^{2} + x - 3 = 0

0 = 36 x^{3} - 49 x

4 x^{3} + 24 x - x - 6 = 0

(b^{2})^{0} = b^{8}

What are the solutions to the equation (x^2+2x+20)^2=0 ?
The solutions to the equation (x^2+2x+20)^2=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i
Find the zeros of (x^2+2x+20)^2=0
The zeros of (x^2+2x+20)^2=0 are x=-1+sqrt(19)i,x=-1-sqrt(19)i