What are the solutions to the equation x^4+5x^2+4x=0 ?

The solutions to the equation x^4+5x^2+4x=0 are x=0,x\approx-0.72407…

Find the zeros of x^4+5x^2+4x=0

The zeros of x^4+5x^2+4x=0 are x=0,x\approx-0.72407…

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x^{4} + 5 x^{2} + 4 x = 0

x = 0, x \approx - 0.72407 \dots

Solution steps

x^{4} + 5 x^{2} + 4 x = 0

Factor

x^{4} + 5 x^{2} + 4 x : x (x^{3} + 5 x + 4)

x (x^{3} + 5 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{3} + 5 x + 4 = 0

Solve

x^{3} + 5 x + 4 = 0 : x \approx - 0.72407 \dots

The solutions are

x = 0, x \approx - 0.72407 \dots

8 x^{4} - 8 x^{3} - 6 x^{2} = 0

x^{5} - 3 x + 9 = 0

x^{3} - 9 x^{2} + 33 x + 45 = 2

x, x^{3} = 729

(y^{2} - y + 1)^{2} = 0

What are the solutions to the equation x^4+5x^2+4x=0 ?
The solutions to the equation x^4+5x^2+4x=0 are x=0,x\approx-0.72407…
Find the zeros of x^4+5x^2+4x=0
The zeros of x^4+5x^2+4x=0 are x=0,x\approx-0.72407…