What are the solutions to the equation 9x^4+82x^2+9=0 ?

The solutions to the equation 9x^4+82x^2+9=0 are x= 1/3 i,x=-1/3 i,x=3i,x=-3i

Find the zeros of 9x^4+82x^2+9=0

The zeros of 9x^4+82x^2+9=0 are x= 1/3 i,x=-1/3 i,x=3i,x=-3i

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9 x^{4} + 82 x^{2} + 9 = 0

x = \frac{1}{3} i, x = - \frac{1}{3} i, x = 3 i, x = - 3 i

Solution steps

9 x^{4} + 82 x^{2} + 9 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

9 u^{2} + 82 u + 9 = 0

Solve

9 u^{2} + 82 u + 9 = 0 : u = - \frac{1}{9}, u = - 9

u = - \frac{1}{9}, u = - 9

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = - \frac{1}{9} : x = \frac{1}{3} i, x = - \frac{1}{3} i

Solve

x^{2} = - 9 : x = 3 i, x = - 3 i

The solutions are

x = \frac{1}{3} i, x = - \frac{1}{3} i, x = 3 i, x = - 3 i

x^{3} + 2 x^{2} - x - 3 = 0

25 x^{4} - 26 x^{2} + 1 = 0

x^{3} - 3 x^{2} - 33 x + 35 = 0

8 = u^{3}

t^{5} (3 t + 6) = 4 (80 - 2 t)

What are the solutions to the equation 9x^4+82x^2+9=0 ?
The solutions to the equation 9x^4+82x^2+9=0 are x= 1/3 i,x=-1/3 i,x=3i,x=-3i
Find the zeros of 9x^4+82x^2+9=0
The zeros of 9x^4+82x^2+9=0 are x= 1/3 i,x=-1/3 i,x=3i,x=-3i