What are the solutions to the equation r^3-6r^2+12r-8=0 ?

The solutions to the equation r^3-6r^2+12r-8=0 are r=2

Find the zeros of r^3-6r^2+12r-8=0

The zeros of r^3-6r^2+12r-8=0 are r=2

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r^{3} - 6 r^{2} + 12 r - 8 = 0

r = 2

Solution steps

r^{3} - 6 r^{2} + 12 r - 8 = 0

Factor

r^{3} - 6 r^{2} + 12 r - 8 : (r - 2)^{3}

(r - 2)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 2 = 0

Solve

r - 2 = 0 : r = 2

The solution is

r = 2

2 x^{4} + 5 x^{3} + 4 - x^{2} = 0

a^{10} = 15 a^{15}, a^{5} = 5

x^{3} - 9 x^{3} = 8

2 x^{3} + 3 x^{2} - 18 x = 27

- 12 x^{4} - 27 x^{3} = 0

What are the solutions to the equation r^3-6r^2+12r-8=0 ?
The solutions to the equation r^3-6r^2+12r-8=0 are r=2
Find the zeros of r^3-6r^2+12r-8=0
The zeros of r^3-6r^2+12r-8=0 are r=2