What are the solutions to the equation 9x^3+x^2-81x-9=0 ?

The solutions to the equation 9x^3+x^2-81x-9=0 are x=-1/9 ,x=-3,x=3

Find the zeros of 9x^3+x^2-81x-9=0

The zeros of 9x^3+x^2-81x-9=0 are x=-1/9 ,x=-3,x=3

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9 x^{3} + x^{2} - 81 x - 9 = 0

x = - \frac{1}{9}, x = - 3, x = 3

Decimal Notation

x = - 0.11111 \dots, x = - 3, x = 3

Solution steps

9 x^{3} + x^{2} - 81 x - 9 = 0

Factor

9 x^{3} + x^{2} - 81 x - 9 : (9 x + 1) (x + 3) (x - 3)

(9 x + 1) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

9 x + 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

9 x + 1 = 0 : x = - \frac{1}{9}

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - \frac{1}{9}, x = - 3, x = 3

x = x^{3} + 1

12 x^{3} = - 3 x^{2} - 12

\frac{256}{3125} x^{5} = 1

4 c^{3} + 24 c^{2} - 64 c = 0

x^{2} - 6 x = 2 x^{2} x

What are the solutions to the equation 9x^3+x^2-81x-9=0 ?
The solutions to the equation 9x^3+x^2-81x-9=0 are x=-1/9 ,x=-3,x=3
Find the zeros of 9x^3+x^2-81x-9=0
The zeros of 9x^3+x^2-81x-9=0 are x=-1/9 ,x=-3,x=3