What are the solutions to the equation y^3+0.5y=0 ?

The solutions to the equation y^3+0.5y=0 are y=0,y= 1/(sqrt(2))i,y=-1/(sqrt(2))i

Find the zeros of y^3+0.5y=0

The zeros of y^3+0.5y=0 are y=0,y= 1/(sqrt(2))i,y=-1/(sqrt(2))i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{3} + 0.5 y = 0

y = 0, y = \frac{1}{2} i, y = - \frac{1}{2} i

Solution steps

y^{3} + 0.5 y = 0

Factor

y^{3} + 0.5 y : y (y^{2} + 0.5)

y (y^{2} + 0.5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y^{2} + 0.5 = 0

Solve

y^{2} + 0.5 = 0 : y = \frac{1}{2} i, y = - \frac{1}{2} i

The solutions are

y = 0, y = \frac{1}{2} i, y = - \frac{1}{2} i

6804 = 3780 (1 + r)^{4}

7 + 10 + 63 - 40 + 89 - 88 + 101 - 140 = x^{5}

x^{3} = 35 (3) + 20

2 x^{4} + 5 x^{2} - 3 = 0

3^{2} + y^{3} = 16 y + 1

What are the solutions to the equation y^3+0.5y=0 ?
The solutions to the equation y^3+0.5y=0 are y=0,y= 1/(sqrt(2))i,y=-1/(sqrt(2))i
Find the zeros of y^3+0.5y=0
The zeros of y^3+0.5y=0 are y=0,y= 1/(sqrt(2))i,y=-1/(sqrt(2))i