What are the solutions to the equation 2x^2-3x-11=0 ?

The solutions to the equation 2x^2-3x-11=0 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4

Find the zeros of 2x^2-3x-11=0

The zeros of 2x^2-3x-11=0 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4

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2 x^{2} - 3 x - 11 = 0

x = \frac{3 + 97}{4}, x = \frac{3 - 97}{4}

Decimal Notation

x = 3.21221 \dots, x = - 1.71221 \dots

Solution steps

2 x^{2} - 3 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 11) = 97

x_{1, 2} = \frac{- ( - 3 ) \pm 97}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 97}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 97}{2 \cdot 2}

x = \frac{- ( - 3 ) + 97}{2 \cdot 2} : \frac{3 + 97}{4}

x = \frac{- ( - 3 ) - 97}{2 \cdot 2} : \frac{3 - 97}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 97}{4}, x = \frac{3 - 97}{4}

r^{2} - 25 = 0

\frac{v}{2} + 9 = 28

(\frac{3}{4}) x + (\frac{2}{5}) = (\frac{1}{2}) x - (\frac{1}{10})

\frac{3}{280} + \frac{1}{150} + \frac{11}{225}

\frac{1}{0.00001}

What are the solutions to the equation 2x^2-3x-11=0 ?
The solutions to the equation 2x^2-3x-11=0 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4
Find the zeros of 2x^2-3x-11=0
The zeros of 2x^2-3x-11=0 are x=(3+sqrt(97))/4 ,x=(3-sqrt(97))/4