What are the solutions to the equation c^3-5c^2+7c-109=0 ?

The solutions to the equation c^3-5c^2+7c-109=0 are c\approx 6.50181…

Find the zeros of c^3-5c^2+7c-109=0

The zeros of c^3-5c^2+7c-109=0 are c\approx 6.50181…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

c^{3} - 5 c^{2} + 7 c - 109 = 0

c \approx 6.50181 \dots

Solution steps

c^{3} - 5 c^{2} + 7 c - 109 = 0

Find one solution for

c^{3} - 5 c^{2} + 7 c - 109 = 0

using Newton-Raphson:

c \approx 6.50181 \dots

Apply long division:

\frac{c ^{3} - 5 c ^{2} + 7 c - 109}{c - 6.50181 \dots} = c^{2} + 1.50181 \dots c + 16.76454 \dots

c^{2} + 1.50181 \dots c + 16.76454 \dots \approx 0

Find one solution for

c^{2} + 1.50181 \dots c + 16.76454 \dots = 0

using Newton-Raphson:

No Solution for

c \in R

The solution is

c \approx 6.50181 \dots

x, f = 5 x^{3} + 1 f (- 8)

- 12 = 5 (6 x^{4}) 7 (x^{6})

(x + 1)^{3} - 27 = 0

5 x^{4} - 19 x + 3 = 2 x - 1

x^{3} - 11 x^{2} + 37 x - 42 = 0

What are the solutions to the equation c^3-5c^2+7c-109=0 ?
The solutions to the equation c^3-5c^2+7c-109=0 are c\approx 6.50181…
Find the zeros of c^3-5c^2+7c-109=0
The zeros of c^3-5c^2+7c-109=0 are c\approx 6.50181…