What are the solutions to the equation (x+1)^3-27=0 ?

The solutions to the equation (x+1)^3-27=0 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2

Find the zeros of (x+1)^3-27=0

The zeros of (x+1)^3-27=0 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2

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(x + 1)^{3} - 27 = 0

x = 2, x = - \frac{5}{2} + i \frac{3 3}{2}, x = - \frac{5}{2} - i \frac{3 3}{2}

Solution steps

(x + 1)^{3} - 27 = 0

Move

27

to the right side

(x + 1)^{3} = 27

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 2, x = - \frac{5}{2} + i \frac{3 3}{2}, x = - \frac{5}{2} - i \frac{3 3}{2}

5 x^{4} - 19 x + 3 = 2 x - 1

x^{3} - 11 x^{2} + 37 x - 42 = 0

- X^{3} + 9 X^{2} - 24 X + 20 = 0

x^{3} + x^{2} = 6 x

(5 x - 2)^{3} - (5 x - 2) = 0

What are the solutions to the equation (x+1)^3-27=0 ?
The solutions to the equation (x+1)^3-27=0 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2
Find the zeros of (x+1)^3-27=0
The zeros of (x+1)^3-27=0 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2