What are the solutions to the equation -λ^3-3λ^2+50λ+150=0 ?

The solutions to the equation -λ^3-3λ^2+50λ+150=0 are λ=-3,λ=-5sqrt(2),λ=5sqrt(2)

Find the zeros of -λ^3-3λ^2+50λ+150=0

The zeros of -λ^3-3λ^2+50λ+150=0 are λ=-3,λ=-5sqrt(2),λ=5sqrt(2)

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- λ^{3} - 3 λ^{2} + 50 λ + 150 = 0

λ = - 3, λ = - 52, λ = 52

Decimal Notation

λ = - 3, λ = - 7.07106 \dots, λ = 7.07106 \dots

Solution steps

- λ^{3} - 3 λ^{2} + 50 λ + 150 = 0

Factor

- λ^{3} - 3 λ^{2} + 50 λ + 150 : - (λ + 3) (λ + 52) (λ - 52)

- (λ + 3) (λ + 52) (λ - 52) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

λ + 3 = 0 or λ + 52 = 0 or λ - 52 = 0

Solve

λ + 3 = 0 : λ = - 3

Solve

λ + 52 = 0 : λ = - 52

Solve

λ - 52 = 0 : λ = 52

The solutions are

λ = - 3, λ = - 52, λ = 52

3 x + 5 x^{6} = 4.5 (x + 6)

0 = 4 x^{3} - 9 x^{2} + 6 x - 1

x^{4} - 3 x^{2} + 2 x - 5 = 0

0 = x^{3} - 2 x + 1

- x^{4} + x^{3} + 45 x^{2} - 25 x - 500 = 0

What are the solutions to the equation -λ^3-3λ^2+50λ+150=0 ?
The solutions to the equation -λ^3-3λ^2+50λ+150=0 are λ=-3,λ=-5sqrt(2),λ=5sqrt(2)
Find the zeros of -λ^3-3λ^2+50λ+150=0
The zeros of -λ^3-3λ^2+50λ+150=0 are λ=-3,λ=-5sqrt(2),λ=5sqrt(2)