What are the solutions to the equation solvefor t,(t^4-1)^2=x ?

The solutions to the equation solvefor t,(t^4-1)^2=x are

Find the zeros of solvefor t,(t^4-1)^2=x

The zeros of solvefor t,(t^4-1)^2=x are

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solve for

t, (t^{4} - 1)^{2} = x

Solution steps

(t^{4} - 1)^{2} = x

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

The solutions are

(1 + x)^{12} = 1.12

(1 + x)^{12} = 1.15

- x^{3} - 36 x^{2} - 416 x - 1552 = 0

x^{3} - x^{2} - x + 5 = 0

(- 2) = x^{3} - 2 x^{2} + 2

What are the solutions to the equation solvefor t,(t^4-1)^2=x ?
The solutions to the equation solvefor t,(t^4-1)^2=x are
Find the zeros of solvefor t,(t^4-1)^2=x
The zeros of solvefor t,(t^4-1)^2=x are