What are the solutions to the equation 2x^4+6x^3-8x^2-24x=0 ?

The solutions to the equation 2x^4+6x^3-8x^2-24x=0 are x=0,x=-3,x=-2,x=2

Find the zeros of 2x^4+6x^3-8x^2-24x=0

The zeros of 2x^4+6x^3-8x^2-24x=0 are x=0,x=-3,x=-2,x=2

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2 x^{4} + 6 x^{3} - 8 x^{2} - 24 x = 0

x = 0, x = - 3, x = - 2, x = 2

Solution steps

2 x^{4} + 6 x^{3} - 8 x^{2} - 24 x = 0

Factor

2 x^{4} + 6 x^{3} - 8 x^{2} - 24 x : 2 x (x + 3) (x + 2) (x - 2)

2 x (x + 3) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 3, x = - 2, x = 2

2 x (x^{3} - 216) = 0

x^{4} + 2 x^{3} - 14 x^{2} + 2 x + 1 = 0

0.5 (5 - 7 x) = 8 - (4 x^{6})

x, x^{4} + y^{4} = 2

125000 (x)^{6} = 165000

What are the solutions to the equation 2x^4+6x^3-8x^2-24x=0 ?
The solutions to the equation 2x^4+6x^3-8x^2-24x=0 are x=0,x=-3,x=-2,x=2
Find the zeros of 2x^4+6x^3-8x^2-24x=0
The zeros of 2x^4+6x^3-8x^2-24x=0 are x=0,x=-3,x=-2,x=2