What are the solutions to the equation 216z^3-1=0 ?

The solutions to the equation 216z^3-1=0 are z= 1/6 ,z=-1/12+1/(4sqrt(3))i,z=-1/12-1/(4sqrt(3))i

Find the zeros of 216z^3-1=0

The zeros of 216z^3-1=0 are z= 1/6 ,z=-1/12+1/(4sqrt(3))i,z=-1/12-1/(4sqrt(3))i

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216 z^{3} - 1 = 0

z = \frac{1}{6}, z = - \frac{1}{12} + \frac{1}{4 3} i, z = - \frac{1}{12} - \frac{1}{4 3} i

Solution steps

216 z^{3} - 1 = 0

Move

1

to the right side

216 z^{3} = 1

Divide both sides by

216

z^{3} = \frac{1}{216}

For

x^{3} = f (a)

the solutions are

Simplify

z = \frac{1}{6}, z = - \frac{1}{12} + \frac{1}{4 3} i, z = - \frac{1}{12} - \frac{1}{4 3} i

3 x^{3} + 5 x^{2} = 2 x

2 x^{3} - x^{2} - 21 x = 0

x^{4} - 20 x^{2} + 100 = 0

x^{3} + 12 x^{2} = - 35 x

t^{3} - t = 0

What are the solutions to the equation 216z^3-1=0 ?
The solutions to the equation 216z^3-1=0 are z= 1/6 ,z=-1/12+1/(4sqrt(3))i,z=-1/12-1/(4sqrt(3))i
Find the zeros of 216z^3-1=0
The zeros of 216z^3-1=0 are z= 1/6 ,z=-1/12+1/(4sqrt(3))i,z=-1/12-1/(4sqrt(3))i