What are the solutions to the equation -x^3-6x^2+6x+28=0 ?

The solutions to the equation -x^3-6x^2+6x+28=0 are x=-2,x=-2+3sqrt(2),x=-2-3sqrt(2)

Find the zeros of -x^3-6x^2+6x+28=0

The zeros of -x^3-6x^2+6x+28=0 are x=-2,x=-2+3sqrt(2),x=-2-3sqrt(2)

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- x^{3} - 6 x^{2} + 6 x + 28 = 0

x = - 2, x = - 2 + 32, x = - 2 - 32

Decimal Notation

x = - 2, x = 2.24264 \dots, x = - 6.24264 \dots

Solution steps

- x^{3} - 6 x^{2} + 6 x + 28 = 0

Factor

- x^{3} - 6 x^{2} + 6 x + 28 : - (x + 2) (x^{2} + 4 x - 14)

- (x + 2) (x^{2} + 4 x - 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 4 x - 14 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 4 x - 14 = 0 : x = - 2 + 32, x = - 2 - 32

The solutions are

x = - 2, x = - 2 + 32, x = - 2 - 32

x^{5} - 6 x^{4} + 11 x^{3} - 6 x^{2} = 0

\frac{x ^{3} + 13}{2} = 20

2 x^{3} + 8 x - 4 x - 40 = 0

x^{3} - 3 x^{2} - 3 x - 4 = 0

(5 x a) (b x^{2}) = 35 x^{8}

What are the solutions to the equation -x^3-6x^2+6x+28=0 ?
The solutions to the equation -x^3-6x^2+6x+28=0 are x=-2,x=-2+3sqrt(2),x=-2-3sqrt(2)
Find the zeros of -x^3-6x^2+6x+28=0
The zeros of -x^3-6x^2+6x+28=0 are x=-2,x=-2+3sqrt(2),x=-2-3sqrt(2)