What are the solutions to the equation (x-2)(x+9)(x-1)=0 ?

The solutions to the equation (x-2)(x+9)(x-1)=0 are x=2,x=-9,x=1

Find the zeros of (x-2)(x+9)(x-1)=0

The zeros of (x-2)(x+9)(x-1)=0 are x=2,x=-9,x=1

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(x - 2) (x + 9) (x - 1) = 0

x = 2, x = - 9, x = 1

Solution steps

(x - 2) (x + 9) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 9 = 0 or x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 9 = 0 : x = - 9

Solve

x - 1 = 0 : x = 1

The solutions are

x = 2, x = - 9, x = 1

(x - 5) (x^{2} + x + 1) = 0

x^{3} + 11 x^{2} + 23 x - 35 = 0

y, x = (y - 2)^{3}

z^{3} = 4 + 4 i 3

9 x^{4} = 12 x^{2} - 4

What are the solutions to the equation (x-2)(x+9)(x-1)=0 ?
The solutions to the equation (x-2)(x+9)(x-1)=0 are x=2,x=-9,x=1
Find the zeros of (x-2)(x+9)(x-1)=0
The zeros of (x-2)(x+9)(x-1)=0 are x=2,x=-9,x=1