What are the solutions to the equation -λ^3+8λ^2-19λ+12=0 ?

The solutions to the equation -λ^3+8λ^2-19λ+12=0 are λ=1,λ=3,λ=4

Find the zeros of -λ^3+8λ^2-19λ+12=0

The zeros of -λ^3+8λ^2-19λ+12=0 are λ=1,λ=3,λ=4

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- λ^{3} + 8 λ^{2} - 19 λ + 12 = 0

λ = 1, λ = 3, λ = 4

Solution steps

- λ^{3} + 8 λ^{2} - 19 λ + 12 = 0

Factor

- λ^{3} + 8 λ^{2} - 19 λ + 12 : - (λ - 1) (λ - 3) (λ - 4)

- (λ - 1) (λ - 3) (λ - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

λ - 1 = 0 or λ - 3 = 0 or λ - 4 = 0

Solve

λ - 1 = 0 : λ = 1

Solve

λ - 3 = 0 : λ = 3

Solve

λ - 4 = 0 : λ = 4

The solutions are

λ = 1, λ = 3, λ = 4

3 x^{3} - 36 x + 3 = 0

3 y^{4} - 5 y^{2} + 1.5 = 0

(x + 1)^{3} = 1

3 x^{3} + 30 x^{2} - 72 x = 0

m^{3} = 10

What are the solutions to the equation -λ^3+8λ^2-19λ+12=0 ?
The solutions to the equation -λ^3+8λ^2-19λ+12=0 are λ=1,λ=3,λ=4
Find the zeros of -λ^3+8λ^2-19λ+12=0
The zeros of -λ^3+8λ^2-19λ+12=0 are λ=1,λ=3,λ=4