What are the solutions to the equation (x+1)^3=1 ?

The solutions to the equation (x+1)^3=1 are x=0,x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2

Find the zeros of (x+1)^3=1

The zeros of (x+1)^3=1 are x=0,x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2

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(x + 1)^{3} = 1

x = 0, x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

Solution steps

(x + 1)^{3} = 1

For

g^{3} (x) = f (a)

the solutions are

Solve

x + 1 = 1 : x = 0

Solve

x + 1 = \frac{- 1 + 3 i}{2} : x = - \frac{3}{2} + i \frac{3}{2}

Solve

x + 1 = \frac{- 1 - 3 i}{2} : x = - \frac{3}{2} - i \frac{3}{2}

The solutions are

x = 0, x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

3 x^{3} + 30 x^{2} - 72 x = 0

m^{3} = 10

u^{3} = 3

u^{3} = 2

4 a^{4} = 8 a^{3} - 8 a^{2}

What are the solutions to the equation (x+1)^3=1 ?
The solutions to the equation (x+1)^3=1 are x=0,x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2
Find the zeros of (x+1)^3=1
The zeros of (x+1)^3=1 are x=0,x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2