What are the solutions to the equation x^3+11x^2+99x+89=0 ?

The solutions to the equation x^3+11x^2+99x+89=0 are x=-1,x=-5+8i,x=-5-8i

Find the zeros of x^3+11x^2+99x+89=0

The zeros of x^3+11x^2+99x+89=0 are x=-1,x=-5+8i,x=-5-8i

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x^{3} + 11 x^{2} + 99 x + 89 = 0

x = - 1, x = - 5 + 8 i, x = - 5 - 8 i

Solution steps

x^{3} + 11 x^{2} + 99 x + 89 = 0

Factor

x^{3} + 11 x^{2} + 99 x + 89 : (x + 1) (x^{2} + 10 x + 89)

(x + 1) (x^{2} + 10 x + 89) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} + 10 x + 89 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 10 x + 89 = 0 : x = - 5 + 8 i, x = - 5 - 8 i

The solutions are

x = - 1, x = - 5 + 8 i, x = - 5 - 8 i

x^{3} = 3 x + 6

17994 = 1624 \cdot (1 + x)^{12}

8 x^{15} + 7 = - 3

x, 2 x^{3} - 3 x = - 10

40 w^{3} - 3 w^{2} - w = 0

What are the solutions to the equation x^3+11x^2+99x+89=0 ?
The solutions to the equation x^3+11x^2+99x+89=0 are x=-1,x=-5+8i,x=-5-8i
Find the zeros of x^3+11x^2+99x+89=0
The zeros of x^3+11x^2+99x+89=0 are x=-1,x=-5+8i,x=-5-8i