What are the solutions to the equation 40w^3-3w^2-w=0 ?

The solutions to the equation 40w^3-3w^2-w=0 are w=0,w=-1/8 ,w= 1/5

Find the zeros of 40w^3-3w^2-w=0

The zeros of 40w^3-3w^2-w=0 are w=0,w=-1/8 ,w= 1/5

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40 w^{3} - 3 w^{2} - w = 0

w = 0, w = - \frac{1}{8}, w = \frac{1}{5}

Decimal Notation

w = 0, w = - 0.125, w = 0.2

Solution steps

40 w^{3} - 3 w^{2} - w = 0

Factor

40 w^{3} - 3 w^{2} - w : w (8 w + 1) (5 w - 1)

w (8 w + 1) (5 w - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

w = 0 or 8 w + 1 = 0 or 5 w - 1 = 0

Solve

8 w + 1 = 0 : w = - \frac{1}{8}

Solve

5 w - 1 = 0 : w = \frac{1}{5}

The solutions are

w = 0, w = - \frac{1}{8}, w = \frac{1}{5}

3 x^{2} - 1 + x^{3} - 1 + x^{5} = 1

0 = x^{3} + 3 x + 2

10 (4 x^{3} - 15 x^{2} + 16 x - 4) = 0

k^{3} - 3 k^{2} + k + 2 = 0

5 = 3 x^{3} + 4 x^{2} + 6 x + 5

What are the solutions to the equation 40w^3-3w^2-w=0 ?
The solutions to the equation 40w^3-3w^2-w=0 are w=0,w=-1/8 ,w= 1/5
Find the zeros of 40w^3-3w^2-w=0
The zeros of 40w^3-3w^2-w=0 are w=0,w=-1/8 ,w= 1/5