What are the solutions to the equation -3x^3+2x^2+8x=0 ?

The solutions to the equation -3x^3+2x^2+8x=0 are x=0,x=-4/3 ,x=2

Find the zeros of -3x^3+2x^2+8x=0

The zeros of -3x^3+2x^2+8x=0 are x=0,x=-4/3 ,x=2

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- 3 x^{3} + 2 x^{2} + 8 x = 0

x = 0, x = - \frac{4}{3}, x = 2

Decimal Notation

x = 0, x = - 1.33333 \dots, x = 2

Solution steps

- 3 x^{3} + 2 x^{2} + 8 x = 0

Factor

- 3 x^{3} + 2 x^{2} + 8 x : - x (3 x + 4) (x - 2)

- x (3 x + 4) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 4 = 0 or x - 2 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - \frac{4}{3}, x = 2

0 = 9 t - t^{3}

x^{4} + 3 = 84

2 x^{4} - x^{3} + x + 2 = 0

- y (1 + y^{2}) = 0

(2 x + 3) (x + 2)^{2} = 4 (2 x + 3)

What are the solutions to the equation -3x^3+2x^2+8x=0 ?
The solutions to the equation -3x^3+2x^2+8x=0 are x=0,x=-4/3 ,x=2
Find the zeros of -3x^3+2x^2+8x=0
The zeros of -3x^3+2x^2+8x=0 are x=0,x=-4/3 ,x=2