What are the solutions to the equation (3x-2)^4=1 ?

The solutions to the equation (3x-2)^4=1 are x=1,x= 1/3

Find the zeros of (3x-2)^4=1

The zeros of (3x-2)^4=1 are x=1,x= 1/3

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(3 x - 2)^{4} = 1

x = 1, x = \frac{1}{3}

Decimal Notation

x = 1, x = 0.33333 \dots

Solution steps

(3 x - 2)^{4} = 1

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 1, x = \frac{1}{3}

- x^{3} + 4 x^{2} - 6 x + 6 = 0

4 x^{2} - 8 x + 4 + x^{4} = 4

x^{3} = 625

7 x = 6 + 5 (3 x + 3) - x^{6} + 5 (3 x + 3) - x

x^{3} - 3 x - 52 = 0

What are the solutions to the equation (3x-2)^4=1 ?
The solutions to the equation (3x-2)^4=1 are x=1,x= 1/3
Find the zeros of (3x-2)^4=1
The zeros of (3x-2)^4=1 are x=1,x= 1/3