What are the solutions to the equation x^3-3x-52=0 ?

The solutions to the equation x^3-3x-52=0 are x=4,x=-2+3i,x=-2-3i

Find the zeros of x^3-3x-52=0

The zeros of x^3-3x-52=0 are x=4,x=-2+3i,x=-2-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 3 x - 52 = 0

x = 4, x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

x^{3} - 3 x - 52 = 0

Factor

x^{3} - 3 x - 52 : (x - 4) (x^{2} + 4 x + 13)

(x - 4) (x^{2} + 4 x + 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x^{2} + 4 x + 13 = 0

Solve

x - 4 = 0 : x = 4

Solve

x^{2} + 4 x + 13 = 0 : x = - 2 + 3 i, x = - 2 - 3 i

The solutions are

x = 4, x = - 2 + 3 i, x = - 2 - 3 i

6 x = x^{3}

5 x^{3} - 14 x^{2} - 3 x = 0

x^{2} (2 x + 1) = 0

x, x^{6} - 16 x^{4} = 0

(x + 1) (x - 3) (x - 2) = 0

What are the solutions to the equation x^3-3x-52=0 ?
The solutions to the equation x^3-3x-52=0 are x=4,x=-2+3i,x=-2-3i
Find the zeros of x^3-3x-52=0
The zeros of x^3-3x-52=0 are x=4,x=-2+3i,x=-2-3i