What are the solutions to the equation 2x^5-20x^3+42x=0 ?

The solutions to the equation 2x^5-20x^3+42x=0 are x=0,x=-sqrt(3),x=sqrt(3),x=-sqrt(7),x=sqrt(7)

Find the zeros of 2x^5-20x^3+42x=0

The zeros of 2x^5-20x^3+42x=0 are x=0,x=-sqrt(3),x=sqrt(3),x=-sqrt(7),x=sqrt(7)

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2 x^{5} - 20 x^{3} + 42 x = 0

x = 0, x = - 3, x = 3, x = - 7, x = 7

Decimal Notation

x = 0, x = - 1.73205 \dots, x = 1.73205 \dots, x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

2 x^{5} - 20 x^{3} + 42 x = 0

Factor

2 x^{5} - 20 x^{3} + 42 x : 2 x (x + 3) (x - 3) (x + 7) (x - 7)

2 x (x + 3) (x - 3) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or x - 3 = 0 or x + 7 = 0 or x - 7 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = - 3, x = 3, x = - 7, x = 7

x, 1 x^{6} - 5 x^{2} = 0

16 x - 2 x^{3} = \frac{16}{3}

0 = x^{6} + 7 x^{4} - 8 x^{2}

3 x^{3} - 19 x^{2} + 36 x - 10 = 0

x^{5} + 2 x^{4} + 6 x^{2} + 1 = 114514

What are the solutions to the equation 2x^5-20x^3+42x=0 ?
The solutions to the equation 2x^5-20x^3+42x=0 are x=0,x=-sqrt(3),x=sqrt(3),x=-sqrt(7),x=sqrt(7)
Find the zeros of 2x^5-20x^3+42x=0
The zeros of 2x^5-20x^3+42x=0 are x=0,x=-sqrt(3),x=sqrt(3),x=-sqrt(7),x=sqrt(7)