What are the solutions to the equation (9x^2+1)^2=0 ?

The solutions to the equation (9x^2+1)^2=0 are x= 1/3 i,x=-1/3 i

Find the zeros of (9x^2+1)^2=0

The zeros of (9x^2+1)^2=0 are x= 1/3 i,x=-1/3 i

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(9 x^{2} + 1)^{2} = 0

x = \frac{1}{3} i, x = - \frac{1}{3} i

Solution steps

(9 x^{2} + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

9 x^{2} + 1 = 0 : x = \frac{1}{3} i, x = - \frac{1}{3} i

The solutions are

x = \frac{1}{3} i, x = - \frac{1}{3} i

2 z^{6} - 15 z^{3} - 27 = 0

(x^{2} + 7 x + 49) (x - 7) = 218

4 x^{3} - 2 x^{2} + 3 x - 1 = 0

x^{3} + 5 x^{2} - 14 x - 70 = 0

x^{3} + 3 x^{2} - 58 = 0

What are the solutions to the equation (9x^2+1)^2=0 ?
The solutions to the equation (9x^2+1)^2=0 are x= 1/3 i,x=-1/3 i
Find the zeros of (9x^2+1)^2=0
The zeros of (9x^2+1)^2=0 are x= 1/3 i,x=-1/3 i