What are the solutions to the equation x^3-4x=3x+6 ?

The solutions to the equation x^3-4x=3x+6 are x=-1,x=-2,x=3

Find the zeros of x^3-4x=3x+6

The zeros of x^3-4x=3x+6 are x=-1,x=-2,x=3

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x^{3} - 4 x = 3 x + 6

x = - 1, x = - 2, x = 3

Solution steps

x^{3} - 4 x = 3 x + 6

Move

6

to the left side

x^{3} - 4 x - 6 = 3 x

Move

3 x

to the left side

x^{3} - 7 x - 6 = 0

Factor

x^{3} - 7 x - 6 : (x + 1) (x + 2) (x - 3)

(x + 1) (x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = - 2, x = 3

(p^{2} - 3)^{2} - 7 (p^{2} - 3) + 6 = 0

25 x^{2} (5 x - 8) - 16 (5 x - 8) = 0

1200 = 360 (1 + x)^{10}

60 \cdot m^{5} = 45

3 x^{4} + 4 x^{3} - 6 x^{2} - 8 x = 0

What are the solutions to the equation x^3-4x=3x+6 ?
The solutions to the equation x^3-4x=3x+6 are x=-1,x=-2,x=3
Find the zeros of x^3-4x=3x+6
The zeros of x^3-4x=3x+6 are x=-1,x=-2,x=3