What are the solutions to the equation 3x^4+4x^3-6x^2-8x=0 ?

The solutions to the equation 3x^4+4x^3-6x^2-8x=0 are x=0,x=-4/3 ,x=-sqrt(2),x=sqrt(2)

Find the zeros of 3x^4+4x^3-6x^2-8x=0

The zeros of 3x^4+4x^3-6x^2-8x=0 are x=0,x=-4/3 ,x=-sqrt(2),x=sqrt(2)

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3 x^{4} + 4 x^{3} - 6 x^{2} - 8 x = 0

x = 0, x = - \frac{4}{3}, x = - 2, x = 2

Decimal Notation

x = 0, x = - 1.33333 \dots, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

3 x^{4} + 4 x^{3} - 6 x^{2} - 8 x = 0

Factor

3 x^{4} + 4 x^{3} - 6 x^{2} - 8 x : x (3 x + 4) (x + 2) (x - 2)

x (3 x + 4) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 4 = 0 or x + 2 = 0 or x - 2 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - \frac{4}{3}, x = - 2, x = 2

(x^{2} - 4)^{2} + 3 x^{2} = 12

4 c^{3} + 4 c^{2} - 80 c = 0

- 12 x^{5} - 6 x^{3} + 10 x + 2 = 0

0 = x^{3} + x^{2} + 5 x - 6

400 y^{2} + y^{6} = 41

What are the solutions to the equation 3x^4+4x^3-6x^2-8x=0 ?
The solutions to the equation 3x^4+4x^3-6x^2-8x=0 are x=0,x=-4/3 ,x=-sqrt(2),x=sqrt(2)
Find the zeros of 3x^4+4x^3-6x^2-8x=0
The zeros of 3x^4+4x^3-6x^2-8x=0 are x=0,x=-4/3 ,x=-sqrt(2),x=sqrt(2)