What are the solutions to the equation 4c^3+4c^2-80c=0 ?

The solutions to the equation 4c^3+4c^2-80c=0 are c=0,c=4,c=-5

Find the zeros of 4c^3+4c^2-80c=0

The zeros of 4c^3+4c^2-80c=0 are c=0,c=4,c=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 c^{3} + 4 c^{2} - 80 c = 0

c = 0, c = 4, c = - 5

Solution steps

4 c^{3} + 4 c^{2} - 80 c = 0

Factor

4 c^{3} + 4 c^{2} - 80 c : 4 c (c - 4) (c + 5)

4 c (c - 4) (c + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c = 0 or c - 4 = 0 or c + 5 = 0

Solve

c - 4 = 0 : c = 4

Solve

c + 5 = 0 : c = - 5

The solutions are

c = 0, c = 4, c = - 5

- 12 x^{5} - 6 x^{3} + 10 x + 2 = 0

0 = x^{3} + x^{2} + 5 x - 6

400 y^{2} + y^{6} = 41

4 x^{3} + 5 x + 3 = 0

z^{4} = - 0.25

What are the solutions to the equation 4c^3+4c^2-80c=0 ?
The solutions to the equation 4c^3+4c^2-80c=0 are c=0,c=4,c=-5
Find the zeros of 4c^3+4c^2-80c=0
The zeros of 4c^3+4c^2-80c=0 are c=0,c=4,c=-5