What is the answer to \sqrt[5]{x^2+2x}=-1 ?

The answer to \sqrt[5]{x^2+2x}=-1 is x=-1

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\sqrt[5]{x^2+2x}=-1

x = - 1

Solution steps

Take both sides of the equation to the power of

5 : x^{2} + 2 x = - 1

x^{2} + 2 x = - 1

Solve

x^{2} + 2 x = - 1 : x = - 1

x = - 1

Verify Solutions:

x = - 1

True

The solution is

x = - 1

x^{2} + x - 2 = 2

2 x + 15 - 6 = x

x = x

x + 15 - x - 15 = 10

(x^{2} - x - 22)^{\frac{4}{3}} = 16

What is the answer to \sqrt[5]{x^2+2x}=-1 ?
The answer to \sqrt[5]{x^2+2x}=-1 is x=-1
Solve for x: \sqrt[5]{x^2+2x}=-1
The solution is x=-1