What are the solutions to the equation 4n^2-12n+9=0 ?

The solutions to the equation 4n^2-12n+9=0 are n= 3/2

Find the zeros of 4n^2-12n+9=0

The zeros of 4n^2-12n+9=0 are n= 3/2

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4 n^{2} - 12 n + 9 = 0

n = \frac{3}{2}

Solution steps

4 n^{2} - 12 n + 9 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

n_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

n = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

n = \frac{3}{2}

The solution to the quadratic equation is:

n = \frac{3}{2}

ln (4) + 1

- 9 = x^{2} + 6 x

2 x = 17

\frac{\frac{14}{( x + h ) ^{2}} - \frac{14}{x ^{2}}}{h}

6 x - 8 = 4 x

What are the solutions to the equation 4n^2-12n+9=0 ?
The solutions to the equation 4n^2-12n+9=0 are n= 3/2
Find the zeros of 4n^2-12n+9=0
The zeros of 4n^2-12n+9=0 are n= 3/2