What is the answer to 4x+2[4-2(x+2)]=2x-4 ?

The answer to 4x+2[4-2(x+2)]=2x-4 is x=2

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4x+2[4-2(x+2)]=2x-4

4 x + 2 [4 - 2 (x + 2)] = 2 x - 4

x = 2

Solution steps

4 x + 2 [4 - 2 (x + 2)] = 2 x - 4

Expand

4 x + 2 (4 - 2 (x + 2)) : 0

0 = 2 x - 4

Move

0

to the right side

= 2 x - 4

Move

2 x

to the left side

- 2 x = - 4

Divide both sides by

- 2

x = 2

2 x^{3} - 18 x - x^{2} y + 9 y

\frac{1}{- \frac{12}{13}}

\frac{4}{7} (x - 5) = 12

(9)^{- \frac{3}{2}}

16 x^{2} - 40 x + 25 = 0

What is the answer to 4x+2[4-2(x+2)]=2x-4 ?
The answer to 4x+2[4-2(x+2)]=2x-4 is x=2
Solve for x: 4x+2[4-2(x+2)]=2x-4
The solution is x=2