What are the solutions to the equation 16x^2-40x+25=0 ?

The solutions to the equation 16x^2-40x+25=0 are x= 5/4

Find the zeros of 16x^2-40x+25=0

The zeros of 16x^2-40x+25=0 are x= 5/4

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16 x^{2} - 40 x + 25 = 0

x = \frac{5}{4}

Solution steps

16 x^{2} - 40 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

(- 40)^{2} - 4 \cdot 16 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 40 )}{2 \cdot 16}

\frac{- ( - 40 )}{2 \cdot 16} = \frac{5}{4}

x = \frac{5}{4}

The solution to the quadratic equation is:

x = \frac{5}{4}

\frac{3}{8} + \frac{3}{8}

x^{2} - 7 x y - 18 y^{2}

5 = 4 - ∣ h + 3 ∣

2 x + 320 = 8 (x - 8)

x^{2} - 2 x = 9

What are the solutions to the equation 16x^2-40x+25=0 ?
The solutions to the equation 16x^2-40x+25=0 are x= 5/4
Find the zeros of 16x^2-40x+25=0
The zeros of 16x^2-40x+25=0 are x= 5/4