What is the answer to 2+sqrt(x)=sqrt(4+x^2) ?

The answer to 2+sqrt(x)=sqrt(4+x^2) is x=0,x\approx 3.22677…

Solve for x: 2+sqrt(x)=sqrt(4+x^2)

The solution is x=0,x\approx 3.22677…

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2 + x = 4 + x^{2}

x = 0, x \approx 3.22677 \dots

Solution steps

2 + x = 4 + x^{2}

Remove square roots

16 x = x^{4} - 2 x^{3} + x^{2}

Solve

16 x = x^{4} - 2 x^{3} + x^{2} : x = 0, x \approx 3.22677 \dots

x = 0, x \approx 3.22677 \dots

Verify Solutions:

x = 0

True

, x \approx 3.22677 \dots

True

The solutions are

x = 0, x \approx 3.22677 \dots

2 x - 1 - x - 1 = 1

5 x + 1 = 14 x + 2

x - 8 + 2 = 7

\frac{1}{2} w + 8 = - 2

What is the answer to 2+sqrt(x)=sqrt(4+x^2) ?
The answer to 2+sqrt(x)=sqrt(4+x^2) is x=0,x\approx 3.22677…
Solve for x: 2+sqrt(x)=sqrt(4+x^2)
The solution is x=0,x\approx 3.22677…