What is the answer to 5-2x=sqrt(2x^2+x-1)-x ?

The answer to 5-2x=sqrt(2x^2+x-1)-x is x=-13,x=2

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5-2x=sqrt(2x^2+x-1)-x

5 - 2 x = 2 x^{2} + x - 1 - x

x = - 13, x = 2

Solution steps

5 - 2 x = 2 x^{2} + x - 1 - x

Remove square roots

25 - 10 x + x^{2} = 2 x^{2} + x - 1

Solve

25 - 10 x + x^{2} = 2 x^{2} + x - 1 : x = - 13, x = 2

x = - 13, x = 2

Verify Solutions:

x = - 13

True

, x = 2

True

The solutions are

x = - 13, x = 2

x + 5 - 3 = 4

2 a - 5 = a - 4

x^{2} - x - 1 = x + 5

2 x - 1 - x - 4 = 2

a x + b x + c = 0

What is the answer to 5-2x=sqrt(2x^2+x-1)-x ?
The answer to 5-2x=sqrt(2x^2+x-1)-x is x=-13,x=2
Solve for x: 5-2x=sqrt(2x^2+x-1)-x
The solution is x=-13,x=2