What is the answer to sqrt(2x-1)-sqrt(x-4)=2 ?

The answer to sqrt(2x-1)-sqrt(x-4)=2 is x=13,x=5

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sqrt(2x-1)-sqrt(x-4)=2

2 x - 1 - x - 4 = 2

x = 13, x = 5

Solution steps

2 x - 1 - x - 4 = 2

Remove square roots

x^{2} - 2 x + 1 = 16 x - 64

Solve

x^{2} - 2 x + 1 = 16 x - 64 : x = 13, x = 5

x = 13, x = 5

Verify Solutions:

x = 13

True

, x = 5

True

The solutions are

x = 13, x = 5

a x + b x + c = 0

4 = 3 x - 2

3 x - x + 6 = 0

x, x + y = x y

x + 3 = 6

What is the answer to sqrt(2x-1)-sqrt(x-4)=2 ?
The answer to sqrt(2x-1)-sqrt(x-4)=2 is x=13,x=5
Solve for x: sqrt(2x-1)-sqrt(x-4)=2
The solution is x=13,x=5