What is 3500(1+(0.0216)/4)^{24} ?

The solution to 3500(1+(0.0216)/4)^{24} is (7*5027^{24})/(5^{93)*2^{70}}

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simplify 3500(1+(0.0216)/4)^{24}

simplify

3500 (1 + \frac{0.0216}{4})^{24}

\frac{7 \cdot 502 7 ^{24}}{5 ^{93} \cdot 2 ^{70}}

Solution steps

3500 (1 + \frac{0.0216}{4})^{24}

Simplify

1 + \frac{0.0216}{4} : \frac{5027}{5000}

= 3500 (\frac{5027}{5000})^{24}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{5027}{5000})^{24} = \frac{502 7 ^{24}}{500 0 ^{24}}

= 3500 \cdot \frac{502 7 ^{24}}{500 0 ^{24}}

3500 \cdot \frac{502 7 ^{24}}{500 0 ^{24}} = \frac{7 \cdot 502 7 ^{24}}{5 ^{93} \cdot 2 ^{70}}

= \frac{7 \cdot 502 7 ^{24}}{5 ^{93} \cdot 2 ^{70}}

2 x^{2} - 24 x + 54 = 0

(\frac{1}{3})^{0}

\frac{8 π}{9} + \frac{4 π}{3}

m^{2} - 4 m - 21

2 3^{2}

What is 3500(1+(0.0216)/4)^{24} ?
The solution to 3500(1+(0.0216)/4)^{24} is (7*5027^{24})/(5^{93)*2^{70}}