What is the answer to 4=sqrt((x-4)^2+(-2-1)^2) ?

The answer to 4=sqrt((x-4)^2+(-2-1)^2) is x=4+sqrt(7),x=4-sqrt(7)

Solve for x: 4=sqrt((x-4)^2+(-2-1)^2)

The solution is x=4+sqrt(7),x=4-sqrt(7)

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4 = (x - 4)^{2} + (- 2 - 1)^{2}

x = 4 + 7, x = 4 - 7

Decimal Notation

x = 6.64575 \dots, x = 1.35424 \dots

Solution steps

4 = (x - 4)^{2} + (- 2 - 1)^{2}

Square both sides:

16 = x^{2} - 8 x + 25

16 = x^{2} - 8 x + 25

Solve

16 = x^{2} - 8 x + 25 : x = 4 + 7, x = 4 - 7

x = 4 + 7, x = 4 - 7

Verify Solutions:

x = 4 + 7

True

, x = 4 - 7

True

The solutions are

x = 4 + 7, x = 4 - 7

x - 13 x + 42 = 0

2 x^{2} - 3 x + 1 = 0

x = x - 2

5 x + 3 = 2 x

8 = u

What is the answer to 4=sqrt((x-4)^2+(-2-1)^2) ?
The answer to 4=sqrt((x-4)^2+(-2-1)^2) is x=4+sqrt(7),x=4-sqrt(7)
Solve for x: 4=sqrt((x-4)^2+(-2-1)^2)
The solution is x=4+sqrt(7),x=4-sqrt(7)